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How a 2-1 Multiplexer (MUX) Work?
This article is about a question of how a 2-1 multiplexer work. We collect some answer from the Internet for you to reference.
The description of the question is shown below:
I haven't done EE for quite a long time. I need to implement some MUX, so I started with a two-way MUX. But I don't understand how to make the decision:
A truth table will show that
This truth table shows that when S=0 then Z=A but when S=1 then Z=B.
I don't get the logic here. The boolean expression is Z = (A and S') or (B and S)
Let S = 0, then each sub expression will become
Boolean value in this question
Can someone please explain to me how do we reach that conclusion? Thank you very much!
The most popular answer we collect is that “Your exact question is not clear. The boolean expression is correct. BUT the last two lines MAY be incorrect depending on what you mean by them - eg Z1 and Z2 are undefined and what you mean by them is uncertain. You may find it useful to introduce "don't care" states. Essentially, while the boolean expression is correct you have really got a don't care state when the related mux controls are not activated.”
And the best way to get a proper understanding is to write down the truth table completely. You have 3 inputs (A, B, S), so this will give you 23 = 8 combinations:
Best way to get a proper understanding
It's often useful to add intermediate results to make things more clear. I added a term C = (A ∧ S') and D = (B ∧ S). Now it should be clear that Z = (C ∨ D).
If this question is what you encountering or the answer we collect help you, please pay attention to our website.
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